ILLUSTRATIVE ESTIMATE
Check a turning operation
Assume ap = 2.0 mm, f = 0.20 mm/rev, kc = 2,500 N/mm², C = 1.0, vc = 120 m/min and η = 0.80. Then A = 0.40 mm², Fc ≈ 1,000 N, Pc ≈ 2.0 kW and P1 ≈ 2.5 kW.
A first machine-tool check links the uncut chip area to cutting force, cutting power and required drive power. It is an engineering estimate for selecting and checking a process—not a substitute for tool-maker data or a machine capability curve.
| Step | Turning estimate | Engineering check |
|---|---|---|
| Chip area | A = ap · f | Use cutting depth and feed per revolution in millimetres; the result is in mm². |
| Chip thickness | h = f · sin κr | The cutting-edge angle changes chip thickness and therefore the applicable specific cutting force. |
| Cutting force | Fc = A · kc · C | Select kc for the work material and chip thickness; apply the stated correction factor. |
| Cutting power | Pc = Fc · vc / 60,000 | With force in N and speed in m/min, power is obtained in kW. |
| Required drive power | P1 = Pc / η | Use the relevant machine efficiency and retain margin for the actual duty cycle. |
Assume ap = 2.0 mm, f = 0.20 mm/rev, kc = 2,500 N/mm², C = 1.0, vc = 120 m/min and η = 0.80. Then A = 0.40 mm², Fc ≈ 1,000 N, Pc ≈ 2.0 kW and P1 ≈ 2.5 kW.